A horizontal rope is tied to two supports. From the rope hung five simple pendul

Question

A horizontal rope is tied to two supports. From the rope hung five simple pendulums with different lengths of 25 cm, 50 cm, 1.00 m, 1.50 m and 2.00 m. A horizontal rope is tied laterally other hanging rope through a pulley, a mass-spring system with mass of 0200 kg and spring constant of 7.90 N / m. The spring is stretched and released, and the mass starts to oscillate vertically, pulling the rope regularly horizontal.Después a few seconds one of the pendulum begins to swing significantly. The pendulum swing is long:

Explanation / Answer

The mass of mass-spring system is m = 0.2 kg and the spring constant is k = 7.90 N/m The force acting on the mass is F = m * a or k * x = m * a or a = (k * x/m) where a is the acceleration of the mass and x is the distance through which the spring is stretched The length of the pendulums is l1 = 0.25 m,l2 = 0.50 m,l3 = 1.0 m,l4 = 1.5 m and l5 = 2.0 m The time period of the pendulum swing is T = 2p * (l/a)^1/2

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.