A horizontal force of 750 N is needed toovercome the force of static friction be

Question

   A horizontal force of 750 N is needed toovercome the force of static friction between a level floor and a 250kg crate. What is the acceleration of thecrate if the 750 N force is maintained after the crate begins tomove and the coefficient of kinetic friction is 0.12?    A horizontal force of 750 N is needed toovercome the force of static friction between a level floor and a 250kg crate. What is the acceleration of thecrate if the 750 N force is maintained after the crate begins tomove and the coefficient of kinetic friction is 0.12?

Explanation / Answer

   Force on movingcrate   F   =   Appliedforce   -   force due to kineticfriction    F   =   750   -   k* m *g   =   750   -   0.12* 250 *9.8   =   456   N    Acceleration   a   =   F/m   =   456/ 250   =   1.826   m/s2

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