A car\'s gasoline tank has the shape of a right rectangular box with a square ba

Question

A car's gasoline tank has the shape of a right rectangular box with a square base whose sides measure 60 cm. Its capacity is 53 L. If the tank has only 3.5 L remaining, how deep is the gasoline in the tank, assuming the car is parked on level ground? What do they mean by the shape of the tank? is the base 60x60 or are the sides 60cm high? So you can convert the Capacity and remaining into m^3 Capacity= .053 m3 Left= .0035 m3 the base is 360m2? how do I put all of this information toghether into a formula to determine the depth of the gas tank?

Explanation / Answer

it said that base is square whose sides measure 60cm. you are right: base is 60cm x 60cm = 0.6 m x 0.6 m = 0.36 m^2 if capacity is 53l = 53 dm^3 = 53 (0.1 m)^3 = 53 * 0.001 m^3 = 0.053 m^3 (correct again.) from here, you determine the height of whole tank: base*height = volume ===> height = volume/base = 0.053 m^3/0.36 m^2 = 0.147m if only 3.5l are remaining, that means that you have some height of gasoline in tank: height. using same method: h'=volume'/base = 3.5l/0.36m^2=0.0035m^3/0.36m^2=0.0097m This means that there are 9.7 millimeters of gasoline in tank. get to the gas station :)

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