An attacker at the base of a castle wall 3.65 m high throws a rock straight up w

Question

An attacker at the base of a castle wall 3.65 m high throws a rock straight up with a speed 7.40 m/s from a height of 1.55 m above the ground. (a)Will the rock reach the top of the wall? (b)If so, what is its speed at the top? If not, what initial speed must it have to reach the top? (c)Find the change of speed of a rock thrown straight down from the top of the wall at an initial speed of 7.40 m/s and moving between the same two points. (d)Does the change in speed of the downward-moving rock agree with the magnitude of the speed change of the rock moving upward between the same elevations? (e)Explain physically why it does or does not agree.

Explanation / Answer

Hi, the problem is too long.. this was on my exam and i still had the answer.. and i uploaded it as docs.. download it from here..try any of the links below
http://www.mediafire.com/?83ad74x37vpk69f http://www.mediafire.com/?83ad74x37vpk69f http://www.mediafire.com/file/83ad74x37vpk69f/Here%20is%20your%20answer%20buddy.docx http://www.mediafire.com/file/83ad74x37vpk69f/Here%20is%20your%20answer%20buddy.docx good luck let me know if you need any more help

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