(a) What does the balance read when the elevator is ascending with a constant sp
ID: 1688031 • Letter: #
Question
(a) What does the balance read when the elevator is ascending with a constant speed of 37 m/s?(b) What does the balance read when the elevator is descending with a constant speed of 36 m/s?
(c) What does the balance read when the elevator is ascending at 36 m/s and gaining speed at a rate of 10 m/s2?
(d) Suppose that from t = 0 to t = 4.3 s, the elevator ascends at a constant speed of 10 m/s. Its speed is then steadily reduced to zero during the next 4.6 s, so that it is at rest at t = 8.9 s. Describe the reading of the scale during the interval 0 < t < 8.9 s.
to to 4.3= t4.3 to t8.9=
Explanation / Answer
We know, by Newton's first law, that F = ma. And a force is measured in Newtons. a) The elevator is ascending with constant speed, there are no accelerations except for gravity. The balance will read F=ma with a = g. b) Same as a) c) There are 2 accelerations here, gravity and the elevator which is going upwards The balance should read F = m( g+ acceleration ) d) From t =0 to t=4.3 there are no accelerations except for gravity ( see a) and b) ). The speed of the elevator goes from 10 m/s to 0 m/s in the next 4.6s. The deacceleration is steady so we can calculate is by dividing the speed by the time just as you would calculate a speed by dividing a distance by a time. You are finding the rate at which the speed is changing. The deacceleration goes against gravity so the balance should read F = m(g - (deacceleration)).Related Questions
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