dueTwo blocks with masses M_1 and M_2 hang one under the other. For this problem

Question

dueTwo blocks with masses M_1 and M_2 hang one under the other. For this problem, take the positive direction to be upward, and use g for the magnitude of the acceleration to gravity.

Case 1: The blocks are at rest.
Part A
Find T_2, the tension in the lower rope.
Express your answer in terms of some or all of the variables M_1, M_2, and g.
T_2 =


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Part B
Find T_1, the tension in the upper rope.
Express your answer in terms of some or all of the variables M_1, M_2, and g.
T_1 =


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FeedbackVariables are case sensitive. Check to make sure you are using the correct case.

Case 2: The blocks are now accelerating upward (due to the tension in the strings) with acceleration of magnitude a.
Part C
Find T_2, the tension in the lower rope.
Express your answer in terms of some or all of the variables M_1, M_2, a, and g.
T_2 =


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Part D
Find T_1, the tension in the upper rope.
Express your answer in terms of some or all of the variables M_1, M_2, a, and g.
T_1 =


submithintsshow answer

Explanation / Answer

CASE1:: blocks at rest: PART A :: T2 supports only lower block so T2 = M2 g PART B: T1 supports both blocks so . T_1 = T_2 + M_1 g = M_1 g + M_2 g . T2 supports only lower block so T2 = M2 g . CASE2)):: PART C]]:: Now the tension must also allow the blocks toaccelerate so... .When we have an upward acceleration, we need to add intertia: T_2 = M_2g + M_2a = M_2 (a +g) PART D :: T_1 = M_2( a+g) + M_1(a+g) = (M_1 + M_2) ( a + g ) .

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