A small object carrying a charge of (-55.0)µC experiences a downward force of 6.

Question

A small object carrying a charge of (-55.0)µC experiences a downward force of 6.20e-9 N when placed at a certain point in an electric field. a) What would be the magnitude and direction of the electric field? ans: 1.13e-4 N/C upward b) What would be the magnitude and direction of the force acting on a copper nucleus (atomic number = 29, atomic = 63.5 g/mol) placed at this same point in the electric field? ans: 5.23e-22 Please provide a detailed solution. Thanks.
A small object carrying a charge of (-55.0)µC experiences a downward force of 6.20e-9 N when placed at a certain point in an electric field. a) What would be the magnitude and direction of the electric field? ans: 1.13e-4 N/C upward b) What would be the magnitude and direction of the force acting on a copper nucleus (atomic number = 29, atomic = 63.5 g/mol) placed at this same point in the electric field? ans: 5.23e-22 Please provide a detailed solution. Thanks.

Explanation / Answer

charge q = -55.0µC = -55* 10^-6 C force F = 6.20* 10^-9 N In an electric field F = Eq from this electric field E = F/ q plug the values we get E = 1.127*10^-4 N / C ~ 1.13 * 10^-4 N / C force on negative charge is opposite to field direction So, direction of E is upward b) magnitude of the force acting on a copper nucleus F ' = Eq ' where q' = charge on copper nucleus = 29 e = 29 * 1.6 * 10^-19C So, F ' = 5.23* 10^-22 N

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.