Hello. My name is Jason and I am taking physics online. I hesitated to take this

Question

Hello. My name is Jason and I am taking physics online. I hesitated to take this online but I couldn't squeeze it into my schedule. I am one month into it and I am starting to have trouble.My question is.
"A 10kg block rests on a surface.coeff of static friction is .4 What is the max friction force that the surface can produce? What is the minimum force needed to get the block sliding? If a a force of 50N is applied horizontally to the block, what is the resaulting acceleration? Use coeff on kenetic is 1/2 coeff of static.(uk=1/2us)

Explanation / Answer

Given Mass of the block, m= 10 kg coefficient of static friction,µs = 0.4 The maximum frictional force is fmax = µs mg = 0.4 * 10 kg *9.8 m/s^2                    = 39.2 N The minimum force needed to get the block sliding is F = fr = µk mg         = 0.2 * 10 kg *9.8 m/s^2 =19.6 N ----------------------------------------------------------------------------- If a force F1 = 50 N is applied horizontally, then the net force is F = F1 - µk mg = 50 N - ( 0.2 * 10 kg *9.8 m/s^2 ) ma =30.4 Acceleration, a = 30.4 /10 kg =3.04 m/s^2

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