You are asked to consult for the city\'s research hospital, where a group of doc

Question

You are asked to consult for the city's research hospital, where a group of doctors is investigating the bombardment of cancer tumors with high-energy ions. The ions are fired directly toward the center of the tumor at speeds of 4.5 times 10^6. To cover the entire tumor area, the ions are deflected sideways by passing them between two charged metal plates that accelerate the ions perpendicular to the direction of their initial motion. The acceleration region is 5.0 cm long, and the ends of the acceleration plates are 1.5 m from the patient. What acceleration is required to move an ion 2.0 cm to one side?

Explanation / Answer

Given The speed of of the ions, v = 4.5 *10^6 m/s The accelerate region, s =0.05 m long The time taken for the acceleration, t1 = s/v    t1 = 0.05 m/(4.5 *10^6 m/s)    t1   = 0.01 *10 ^-6 s since the acceleration is perpendicular to original velocity, the velocity in y axis remains unchanged.so the time taken to reach the body is t2 = 1.5/(4.5 *10^6 m/s) =0.33 * 10^-6 s The velocity in x direction is v = s/t = 0.02 m/(0.33 * 10^-6 s) =0.06 *10^6 m/s v = 6 *10^4 m/s The acceleration required to move an ion 0.02 m to one side is a = v/t1 a = (6 *10^4 m/s)/(0.01 *10 ^-6 s) a = 6 *10^12 m/s^2                                                  

Related Questions

Navigate

• Browse (All)
• Browse Y
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.