A 79.0 kg person stands on a scale in an elevator. What is the apparent weight i

Question

A 79.0 kg person stands on a scale in an elevator. What is the apparent weight in each of the following situations? a) When the elevator is accelerating upward with an acceleration of 1.50 m/s2 b) When the elevator is moving upward at a constant speed c) When the elevator is accelerating downward with an acceleration of 2.00 m/s2 A 79.0 kg person stands on a scale in an elevator. What is the apparent weight in each of the following situations? a) When the elevator is accelerating upward with an acceleration of 1.50 m/s2 b) When the elevator is moving upward at a constant speed c) When the elevator is accelerating downward with an acceleration of 2.00 m/s2

Explanation / Answer

m=79 kg T=tension a=accelertaion( 1.50 m/s2) a] W=mg and so your mass is 79kg and so then you multiply thatmass by 9.81m/s2 so if your question is tension you must have T=(79 kg)x(1.9)=150.1 N b] moving with constant speed, then weight = 79 kg c] T=(79kg)x(-2 m/s2)=-158 N hope this helps if you have further questions message me illget back to you asap

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