A person stands on a scale in an elevator. As the elevator starts, the scale has

Question

A person stands on a scale in an elevator. As the elevator starts, the scale has a constant reading of 582 N. As the elevator later stops, the scale reading is 390 N. Assume the magnitude of the acceleration is the same during starting and stopping.
What is the persons weight.
I know that weight is equal to the mass of the person times the gravity, but mass isnt given so it must be found. After making force diagrams for each of the situations you know that the sum of the forces on the person when the elevator is going up is equal to 582N which is equal to the N-mg. I'm just not really sure where to go from there.

Explanation / Answer

Weight, W= mg = 972/2 = 486 Please rate

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