You are at a golf course driving range when you hit a golf ball with you favorit

Question

You are at a golf course driving range when you hit a golf ball with you favorite titanium shafted club. You observe the angle of elevation of the launch velocity from ground level to be 40.0 degrees and the ball striking level ground downrange at exactly the 325 m marker (by the way your in England). Suddenly you notice the ball chaser in his little cart with a cage that just happens to have a target painted on it with a bull-seye exactly 2.10 m above the ground moving from you right to left in line with the 200 m marker. If the ball chaser is moving at a maximum speed (which is 21.5 mph) perpindicular to the line between you and the 200 m marker, where should the ball chaser be and at what angle of elevation should you strike the ball so you hit the bull's eye when the ball chaser is exactly in line with the 200 m marker? (Assume no air resistance for this type of problem. Also, assume you strike the ball in an identical fasion each time, and be very clear about the direction of the initial velocity you impart to the golf ball.)

Explanation / Answer

vo=((9.8*325^2)/(2*cos(40)^2*(325*tan(40)))^1/2=56.87 m/s 21.5 mph=9.6 m/s theta needed to hit the cart at 200 m is 18.65 degrees for vo = 56.87 m/s vox=56.87*cos(18.65 degrees)=53.88 m/s t=200 m / 53.88 m/s=3.712 s the cart will be at 9.6 m/s * 3.712 s =35.63 m down range theta to hit the golf ball is tan^(-1)(35.63/200)=10.103 degrees angle on the grd to hit cart is leading the cart by 10.1 degrees, from start of cart perpendicular to golfer

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