An inclined plane, fixed to the inside of an elevator, makes a 40 degree angle w

Question

An inclined plane, fixed to the inside of an elevator, makes a 40 degree angle with the floor. A mass m slides on the plane without friction.
Part A)
What is its acceleration relative to the plane if the elevator accelerates upward at 0.35 g?

Part B
What is its acceleration relative to the plane if the elevator accelerates downward at 0.35 g?

Part C
What is its acceleration relative to the plane if the elevator falls freely?
ANSWER: = 0

Part D
What is its acceleration relative to the plane if the elevator moves upward at constant speed?

Please solve all the way through and show the steps An inclined plane, fixed to the inside of an elevator, makes a 40 degree angle with the floor. A mass m slides on the plane without friction.
Part A)
What is its acceleration relative to the plane if the elevator accelerates upward at 0.35 g?

Part B
What is its acceleration relative to the plane if the elevator accelerates downward at 0.35 g?

Part C
What is its acceleration relative to the plane if the elevator falls freely?
ANSWER: = 0

Part D
What is its acceleration relative to the plane if the elevator moves upward at constant speed?

Please solve all the way through and show the steps

Explanation / Answer

Part A. You use the sine of 40= opposite (the upward motion of 3.5 g) over hypotenuse (acceleration relative to the plane) and get sine40=x .35 Multiply the sine of 40 by .35 and get .225 g as the answer. Part B. Just do the opposite of the above problem. The answer is -.225 g Part C. It's 0 because it is falling in line with the elevator. Part D. It would be again 0 because if there is no acceleration (the velocity is constant) then it would move in turn with it. I hope this helped!!!

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