A 730 N man stands in the middle of a frozen pond of radius 8.0 m. He is unable

Question

A 730 N man stands in the middle of a frozen pond of radius 8.0 m. He is unable to get to the other side because of a lack of friction between his shoes and the ice. To overcome this difficulty, he throws his 1.2 kg physics textbook horizontally toward the north shore at a speed of 8.0 m/s. How long does it take him to reach the south shore?

High-speed stroboscopic photographs show that the head of a 220 g golf club is traveling at 42 m/s just before it strikes a 46 g golf ball at rest on a tee. After the collision, the club head travels (in the same direction) at 33 m/s. Find the speed of the golf ball just after impact.


A railroad car of mass 2.50 104 kg moving at 2.50 m/s collides and couples with two coupled railroad cars, each of the same mass as the single car and moving in the same direction at 1.20 m/s.
(a) What is the speed of the three coupled cars after the collision?
(b) How much kinetic energy is lost in the collision?


A 730 N man stands in the middle of a frozen pond of radius 8.0 m. He is unable to get to the other side because of a lack of friction between his shoes and the ice. To overcome this difficulty, he throws his 1.2 kg physics textbook horizontally toward the north shore at a speed of 8.0 m/s. How long does it take him to reach the south shore?

High-speed stroboscopic photographs show that the head of a 220 g golf club is traveling at 42 m/s just before it strikes a 46 g golf ball at rest on a tee. After the collision, the club head travels (in the same direction) at 33 m/s. Find the speed of the golf ball just after impact.


A railroad car of mass 2.50 104 kg moving at 2.50 m/s collides and couples with two coupled railroad cars, each of the same mass as the single car and moving in the same direction at 1.20 m/s.
(a) What is the speed of the three coupled cars after the collision?
(b) How much kinetic energy is lost in the collision?

Explanation / Answer

The mass of the man m1 = 730/9.8 = 74.5 kg the mass of the physics text book m2 = 1.2kg the speed of the book v2 = 8.0m/s From law of conservation of momentum m1v1 + m2v2 = 0 so m1v1 = -m2v2 then the speed of the man v1 = -m2v2 / m1 = (1.2)(8) / 74.5 = 0.128 m/s Here sign indicates the direction opposite to the book direction the time taken to reach the shore t = d/ = 8.0 / 0.128 = 62.5sec

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