A quarterback throws a football toward a reciever with an initial speed of 20.5m

Question

A quarterback throws a football toward a reciever with an initial speed of 20.5m/s at an angle of 30deg above the horizontal. At the instant the ball is thrown, the receiver is 21.0m downfield from the quarterback:
a. What are the horizonal and verticle components of the initial velocity of the ball; b. After 1.00s, how far above the height it was thrown is the ball?;
c. What is the verticle component of speed when the ball reachers the reviever's original location at 21.0m downfield?;
d. What is the time of flight for the ball, assuming it is caught at te same level at hich it was thrown?;
e. With what constant speed much the reciever run to catch the ball?

Explanation / Answer

a) if you were to draw this situation on an x/y axis..you draw the vector for initial velocity starting at the origin. you realize that this vector has a magnutude of 20.5 m/s and is at an angle of 30 degrees above the positive x axis. to break this single vector into its horizontal and vertical components, follow this procedure for the x component: multiply the magnitude of the vector by the cosine of its angle.... 20.5 x cos(30) = 17.75 m/s

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