two packing crates of masses m1 = 10.0 kg and m2 = 5.50 kg are connected by a li

Question

two packing crates of masses m1 = 10.0 kg and m2 = 5.50 kg are connected by a light string that passes over a frictionless pulley as in the figure below. The 5.50 kg crate lies on a smooth incline of angle 45.0°. Find the acceleration of the 5.50 kg crate.Find the tension in the string.

Explanation / Answer

to find a---> ((wb-wa)*sin(45 degrees))/(ma+mb)= ((10 kg*9.8 m/s^2-5.5 kg*9.8 m/s^2)*sin(45 degrees))/(5.5 kg+10 kg)=2.01183 m/s^2 a=2.01183 m/s^2 -T=10*2.01183-10*9.8=-77.8817 or 77.8817 because of the frictionless pulley both crates have the same T T=77.8817 if the crates were falling at time = 2 sec the y distance would be y=1/2*ay*t^2=1/2*2.01183*2^2=4.02367 m voy=0

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