A beam with a length of 9 m and a mass of 112 kg is attached by a large bolt to

Question

A beam with a length of 9 m and a mass of 112 kg is attached by a large bolt to a support at a distance of d = 3 m from one end. The beam makes an angle ? = 30° with the horizontal, as shown in the figure. A mass
M = 504 kg
is attached with a rope to one end of the beam, and a second rope is attached at a right angle to the other end of the beam. (Let up be the +y-direction and to the right be the +x direction.)

Find the tension, T, in the second rope.


Find the force exerted on the beam by the bolt. (Indicate the direction with the sign of your answer.)
Fbx =
Fby =

Explanation / Answer

Net torque about the pivot point be zero. so T*6+504*3*9.8*cos30=112*9.8*1.5*cos30 so T=-1900(N). ------ net vertical force is zero. so F_by=(504+112)*9.8-T*cos30=7680(N)> net horizontal force is zero. F_bx=T*sin30=950(N)

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