A beam of protons traveling at 1.20km/s enters a uniform magnetic field, traveli

Question

A beam of protons traveling at 1.20km/s enters a uniform magnetic field, traveling perpendicular to the field. The beam exits the magnetic field, leaving the field in a direction perpendicular to its original direction (the figure (Figure 1) ). The beam travels a distance of 1.40cm while in the field.

What is the magnitude of the magnetic field?

A beam of protons traveling at 1.20km/s enters a uniform magnetic field, traveling perpendicular to the field. The beam exits the magnetic field, leaving the field in a direction perpendicular to its original direction (the figure (Figure 1) ). The beam travels a distance of 1.40cm while in the field. What is the magnitude of the magnetic field?

Explanation / Answer

1.40 x 10-2 = pi x r / 2

r = 7.64 x 10-3 m

F = qvB = mv^2 / r

1.6 x 10-19 x B = 1.673 x 10-27 x 1.20 x 10^3 / (7.64 x 10^-3)

B = 1.64 x10-3 T

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