please try to explaing in detail, thank you very much in advance, A square curre
ID: 1698263 • Letter: P
Question
please try to explaing in detail, thank you very much in advance,
A square current loop lies flat in the x-y plane with its sides parallel to the x and y axes. The side of the square is a. The current flowing in the loop is in the CCW direction as viewed from above. A uniform magnetic field B = Bo(i/ + k/ ) is applied to the loop. Find the magnetic force (magnitude and direction) on each side of the loop. Check that the sum of the four forces equals zero. What is the magnetic dipole moment (magnitude and direction) of the loop? Find the torque (magnitude and direction) on the current loop.Explanation / Answer
a) We know that F=l*IxB. 4 sides of the loop. I*(ai) I*(aj) I*(-ai) I*(-aj) F=I*(l)x(B) (inside() mean vector) so F1=-I*a*B0*j/sqrt(2) F2=I*a*B0*(-k+i)/sqrt(2) F3=I*a*B0*j/sqrt(2) F4=I*a*b0*(k-i)/sqrt(2). ------- the current go CCW so vector I*a^2 have the direction of -k -k*I*a^2 ---- T=mxB (-k*I*a^2)xB0*(i+k)/sqrt(2) =-j*I*a^2*B0/sqrt(2)
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