please try to answer part B and part C thank you 3410 points Previous Answers Se
ID: 1784437 • Letter: P
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please try to answer part B and part C thank you
3410 points Previous Answers SerPOP5 22 P 033.MI One long wire carries current 34.0 A to the left along the x axis. A second long wire carries current 78.0 A to the right along the line 0.280 m, z 0) (a) Where in the plane of the two wires is the total magnetic field equal to zero? y-0.22 b) A particle with a charge of 2.00 is moving with a velocity of 150 m s along the lin y 0.100 m o calculate the vector magnetic force acting an the particle Ignore relativ stic effects. (c) A uniform electric fleld is applied to allow this particle to pass through this reglon undeflected. Calculate the required vector electric fleld N/C Need Help? RodtNaster It Subrnit Answer Save Progresrc Another VersionExplanation / Answer
(b)
The magnetic field of the plane formed by the wire is given by
B = [u0*i1/2*pi*r1] + [u0*i1/2*pi*r2]
B = (u0/2*pi*r)[(i1/y) + (i2/(y-0.28)]
at y = 0.100 m
B = (4*pi*10^-7/2*pi)[(34/0.10)(-k) + (78/(0.28-0.10))(-k)]
= 1.54*10^-4 T
The force acting on the partical is given by the equation
F = q*v*B
= (-2*10^-6)*(150*10^6)*(1. 54*10^-4)
= 4.62*10^-2 N (j)
(c)
In the electric field the force acting on the particle is
F = q*E
E = F/q
= (4.62*10^2) / (-2*10^-6)
= - 2.31*10^2 N/C
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