A 160 g hockey puck swings around on the end of a sprins on a frictionless surfa

Question

A 160 g hockey puck swings around on the end of a sprins on a frictionless surface as shown in the diagram One end of the spring is attached to the hockey puck, and the other is attached to a fixed pivot point. The spring has a spring constant of 25 N/m and an equilibrium length of 1m and stietches a distance of 10 cm. Draw a free body diagram for the hockcy puck as viewed from the point of the puck, and indicate the direction of the center of rotation. What is the magnitude of the acceleration of the hockcy puck? What is the magnitude of the velocity of the hockcy puck?

Explanation / Answer

(b) As the spring is stretched by a distance of x, then the spring force is balanced with force acting on the hockey. So kx = ma a = kx / m = (25 N/m)(0.10 m) / (0.160 kg) = 15.6 m/s^2 (b) According to the law of conservation of energy, the amount of energy stored in the spring is balanced with kinetic energy of the puck. That means (1/2)kx^2 = (1/2)mv^2 kx^2 = mv^2 (25N/m)(0.10m)^2 = (0.160kg)v^2 v = 1.25 m/s

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