In an experiment, target ball C has of 0.10kg. The incident ball A slides at 1.4

Question

In an experiment, target ball C has of 0.10kg. The incident ball A slides at 1.4 meters per second, but makes a glancing collision with the target ball C that is at rest at the edge of the table. The target ball C strikes the floor at point P, which is at a horizontal displacement of 0.15 meters from the point of the collision, and at a horizontal angle of 30 degrees from the x axis.

A. Calculate the speed V of the target ball C immediately after the collision
B. Calculate the y component of incident ball A's momentum immediately after the collision

Explanation / Answer

(a) Height of the table top, h = 1.2 m Time of fall, t = sqrt [ 2h/g ] = sqrt [ 2 * 1.2 / 9.8 ] = 0.49 s Velocity of the target ball, V = d / t = 0.15 / 0.49 = 0.31 m/s (b) Y-component of the momentum, P = m v sin theta = 0.1 * 0.31 * sin 30 = 0.015 kg.m/s

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