A “bug-zapper” uses a voltage of 4000V provided by a transformer that is connect

Question

A “bug-zapper” uses a voltage of 4000V provided by a
transformer that is connected to a standard household source of
120Hz.
A) If the primary coil of this transformer has 27 turns, how many
turns must there be in the secondary to provide this output?
B) If one bug electrocution requires a current of 0.2mA, what
current is drawn from the house current and what is the power
required?

Explanation / Answer

Ns/Np=Ip/Is--->V1*I1=V2*I2--->4000*.0002/120=0.006667 A V1/V2=a=I2/I1=0.03--->V1/I1=a*V2/(I2/a)--->4000*0.0002=0.8 W sec. A) Ns/Np=Ip/Is=Ns/27=0.0066667/0.0002--->Ns=900 turns--->27:900 ratio (900/27=1:33.33 ratio, step up transformer) B) house current is 0.006667 A, 0.006667*120=0.8 W pri. and sec for an ideal transformer

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