Question Details A 0.17 kg block oscillates back and forth along a straight line

Question

Question Details
A 0.17 kg block oscillates back and forth along a straight line on a frictionless horizontal surface. Its displacement from the origin is given by
x = (12 cm)cos[(12 rad/s)t + p/2 rad]
(a) What is the oscillation frequency (in Hz)? (b) What is the maximum speed acquired by the block? (c) At what value of x does this occur? (d) What is the magnitude of the maximum acceleration of the block? (e) At what positive value of x does this occur? (f) What force, applied to the block by the spring, results in the given oscillation?
Give your answers in centimeter-based units, where applicable.

(a) 1.9 Hz (correct)
(b) 144 cm/s (correct)
(c) 0 cm (correct)

(d) 1728 cm/s^2 (correct)
(e) 12 cm (correct)
(f) i dont know... help

for (f) i tried hookes law mg=kx and then applied it to Fs=-kx

Explanation / Answer

The force applied on the block due to the spring which accelerated the mass is F = ma F = 0.17 kg*17.28 m/s^2 F = 2.9376 N

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