A rocket blasts off vertically from rest on the launch pad with an upward accele

Question

A rocket blasts off vertically from rest on the launch pad with an upward acceleration of 2.70 m/s2 . At 20.0 s after blastoff, the engines suddenly fail, which means that the force they produce instantly stops.

PART A: How high above the launch pad will the rocket eventually go?

PART B: Find the rocket's velocity at its highest point. V = 0 m/s ( i got which is correct)

PART C: Find the magnitude of the rocket's acceleration at its highest point.

PART D: How long after it was launched will the rocket fall back to the launch pad?

PART E: How fast will it be moving when it does so?

Explanation / Answer

A) 1/2*2.7*202=540 m==>540/2.7=200 s

B) Vo=voy=0 m/s

C) 2.7 m/s2

D) 540/9.8=55.1 s max ht t+200s=255 s

E) (540*2*9.8)=102.9 m/s

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