Jay has two 8 ohm stereo speakers wired in series in the front of his car connec

Question

Jay has two 8 ohm stereo speakers wired in series in the front of his car connected to the 4.0 Voutput of the stereo. a) What is the current through each of the speakers? b) In his garage, Jay finds two more old speakers with resistance f 4 ohms and 16 ohms. He wires each in parallel with the 8-ohm combination. What is the new current through the 8-ohm speakers? c) If the loudness of each speaker is proportional to the amount of power used, how has the loudness of the two 8-ohm speakers changed?

Explanation / Answer

a) two speakers are in series so we have I*(2*R)=U so I=U/2R=4/16=0.25(A). b) still the same, cause the voltage across the two speakers is unchanged. I=0.25A. c) unchanged. ratio 1:1

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