Two charges are located on a horizontal axis. p 1.8 M on +Y axis ! ! ! 2.5uc----

Question

Two charges are located on a horizontal axis.

                         p 1.8 M on +Y axis
                              !
                              !
                              !
2.5uc--------------------------------------2.5uc
!-----------------------!----------------------!
3M 3M
Determine the electric field at p on a verti-
cal axis as shown in the figure above. Up is
the positive direction. The Coulomb constant
is 8.98755 × 109 N · m2/C2.
Answer in units of V/m.

011 (part 2 of 2) 10.0 points
Calculate the vertical component of the elec-
tric force on a -3.9 µC charge placed at point
p.
Answer in units of N.

Explanation / Answer

First we find the , tan = 1.8/3 = 0.6 = 30.96 degree the electric field due to a charge Q at a point p is given by E1 = E1 cas (i) + E1 sin (j) and E2 = E2 cas (-i) + E2 sin the resultant field E = E1 + E2 E = 2 E1sin (j) (since E1 = E2)      = 2*kQ/r^2 sin E =2* 9*10^9*2.5*10^-6/(12.24) sin (j)     = 3.676*10^3 (sin30.96) (j) E = 1.89*10^3 V/m B) we know that the force acting on charge is F = qE = 1.89*10^3*3.9*10^-6 (-j)     = 7.37*10^-3 N (-j) the magnitude of the force F = 7.37*10^-3 N .

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