A certain heat pump has a COP of 5.1 while operating in both heating and cooling
ID: 1706667 • Letter: A
Question
A certain heat pump has a COP of 5.1 while operating in both heating and cooling mode.Suppose the heat pump operates in heating mode on a cold day.
For every 1000 W of power it takes to run the heat pump, how much power is delivered to the inside of the house?
W
How much power is removed from the outside?
W
The same heat pump now operates in cooling mode on a hot day.
For every 1000 W of power it takes to run the heat pump, how much power is removed from the inside of the house?
W
How much power is expelled to the outside?
W
Explanation / Answer
First, consider heating operation :--------------------------------------…
The heat pump absorbs heat from outside , Q sub A , and rejects heat , Q sub R ,
into the house.
COP sub H = Q sub R / W sub HP
Q sub R = ( COP sub H ) ( W sub HP )
Q sub R = ( 5.1 ) ( 1000 ) = 5100 W = 5100 J per sec <--------------------
Q sub A = Q sub H - W sub HP
Q sub A = 5100 - 1000 = 4100 W = 4100 J. per sec. <-----------------------
Now consider operation in cooling mode :
--------------------------------------…
In cooling mode, heat pump absorbs heat, Q sub A , from the house and rejects
heat , Q sub R , to outside.
COP sub C = Q sub A / W sub HP
Q sub A = ( COP sub C ) ( W sub HP )
Q sub A = ( 5.1 ) ( 1000 ) = 5100 W =5100 J. per sec. <---------------------------
Q sub R = Q sub A + W sub HP
Q sub R = 5100 + 1000 = 6100 W = 6100 J per sec. <---------------------------- Suppose the heat pump operates in heating mode on a cold day.
For every 1000 W of power it takes to run the heat pump, how much power is delivered to the inside of the house? 5100 W
How much power is removed from the outside? 4100 W
The same heat pump now operates in cooling mode on a hot day.
For every 1000 W of power it takes to run the heat pump, how much power is removed from the inside of the house? 5100 W
How much power is expelled to the outside? 6100 W
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