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(a) Place a charge of -3.60 µC at point P and find the magnitude and direction o

ID: 1707296 • Letter: #

Question

 

(a) Place a charge of -3.60 µC at point P and find the magnitude and direction of the electric field at the location of q2.

E = N/C



= ° counterclockwise from the positive x-axis



(b) Find the magnitude and direction of the force on q2.

F = N



= ° counterclockwise from the positive x-axis



I Don't know how to do this Please help Me. Thank you. The top part is how i figured out the rest i think its the missing information to solve the bottom part.

(a) Calculate the electric field at P.   Find the magnitude of 1 with Equation 15.6.
E1 = 3.93 105 N/C Vector 1 is vertical, making an angle of 90° with respect to the positive x-axis. Use this fact to find its components. E1x = E1 cos(90°) = 0
E1y = E1 sin(90°) = 3.93 105 N/C Next, find the magnitude of 2, again with Equation 15.6.
E2 = 1.92 105 N/C Obtain the x-component of 2, using the triangle in Figure 15.12 to find cos .
E2x = E2 cos = (1.92 105 N/C)(0.600)
E2x = 1.15 105 N/C Obtain the y-component in the same way, but a minus sign has to be provided for sin because this component is directed downward.
E2y = E2 sin = (1.92 105 N/C)(0.800)
E2y = -1.54 105 N/C Sum the x-components to get the x-component of the resultant vector. Ex = E1x2x = 0 + 1.15 105 N/C
Ex = 1 N/C
+ E Sum the y-components to get the y-component of the resultant vector. Ey = E1y2y = 3.93 105 N/C - 1.54 105 N/C
Ey = 2 N/C
+ E Use the Pythagorean theorem to find the magnitude of the resultant vector.
E = 3 N/C
The inverse tangent function yields the direction of the resultant vector.
= 4°
(b) Find the force on a charge of 2.00 10-8 C placed at P.   Calculate the magnitude of the force (the direction is the same as that of because the charge is positive). F = Eq = E(2.00 10-8 C)
F = 5 N

Explanation / Answer

Let q1 = -3.60 C = -3.6 * 10^-6 C       The second charge is q2 The electric field strength, E = kq/r^2 But here the distance between the two charges is not known. Means 'r' is unknown. So we can not find out E. But interms of 'r' we can write it as                  E = [ 9*10^9*(-3.6) * 10^-6 ] / r^2                   E = ( 32.4 * 10^3 )/r^2 YOU DOES NOT PROVIDE THE CORRECT DATA. PLEASE GIVE SUFFICIENT DATE I WILL GIVE GOOD SOLUTION I WILL GIVE GOOD SOLUTION