Lab Data 0.0017 Please type the process! Load(tsf) Dial change(in) Toatal dial c
ID: 1710527 • Letter: L
Question
Lab Data
0.0017
Please type the process!
Load(tsf) Dial change(in) Toatal dial change(in) Height of sample,h(in) Void ratio,e Fitting time,t50(s) Height of sample(cm) Cv(cm^2/s) 0 0 0 1 1.2200 2.5400 0.1 0.0269 0.0269 0.9731 1.1603 2.4717 0.2 0.0104 0.0373 0.9627 1.1372 900 2.4453 0.0013 0.4 0.0098 0.0471 0.9529 1.1154 804 2.4204 0.0014 0.8 0.0104 0.0575 0.9425 1.0924 732 2.3940 0.0015 1.6 0.0143 0.0718 0.9282 1.0606 673 2.3576 0.0016 3.2 0.0369 0.1087 0.8913 0.9787 606 2.2639 0.0017 6.4 0.0718 0.1805 0.8195 0.8193 516 2.0815 0.0017 12.8 0.0723 0.2528 0.7472 0.6588 420 1.89790.0017
Determine the amount of time required to achieve 80% field consolidation in a 6m thick layer of the same soil tested in the PSU consolidometer overlain by alluvium and underlain by Columbia River Basalt (see rough cross-section below). Assume the soil is subjected to the same load tested during your laboratory session. Alluvium 6m Soil tested in PSU consolidometer Columbia River BasaltExplanation / Answer
Load(tsf) Dial change(in) Toatal dial change(in) Height of sample,h(in) Void ratio,e Fitting time,t50(s) Height of sample(cm) Cv(cm^2/s) t80 0 0 0 1 1.22 2.54 0.1 0.0269 0.0269 0.9731 1.1603 2.4717 0.2 0.0104 0.0373 0.9627 1.1372 900 2.4453 0.0013 604.5531 0.4 0.0098 0.0471 0.9529 1.1154 804 2.4204 0.0014 549.9997 0.8 0.0104 0.0575 0.9425 1.0924 732 2.394 0.0015 502.1891 1.6 0.0143 0.0718 0.9282 1.0606 673 2.3576 0.0016 456.6243 3.2 0.0369 0.1087 0.8913 0.9787 606 2.2639 0.0017 396.2732 6.4 0.0718 0.1805 0.8195 0.8193 516 2.0815 0.0017 335 12.8 0.0723 0.2528 0.7472 0.6588 420 1.8979 0.0017 Cv = (0.848 d^2)x t80 t80 = (0.848 x d^2)/Cv
Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.