Question 8 After five half-lives, the remaining fraction of radioactive isotope

Question

Question 8

After five half-lives, the remaining fraction of radioactive isotope is 1/x where x = A club is formed. After 12 days, 1/4 of the people are still in the club. What is the half - life for the club members? Exactly why is so much energy released when an atom like^235 U undergoes fission? ^222 Radon, a gas, is formed in the subsurface from the decay of ^226 Radium, which is in a solid mineral form. The half life for ^222 Radon to ^218 Polonium is 3.8 days. Essentially none of the ^218 Polonium will be gaseous. Why wouldn't radon be a threat if the half life was 50 days?

Explanation / Answer

Let number of people in club are X

so number of people left in club after 1 half life=X/2

number of people after 2 half life=(1/2)*(X/2) =X/4

so 2 half life=12 days

so half life = 12/2 = 6days

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