The Problem e00 a. Determine the effective flange width \"b for the Left Spandre

Question

The Problem e00 a. Determine the effective flange width "b for the Left Spandrel-Beam shown above, given: 10-0", h 5.0", bw-12"(typ.) & Clear Beam Span :30.0". b. Determine the effective flange width "b" for the Center Beam shown above, given: 10.0", R : 10'4", h :5.5", b-14"(typ.) & Clear Beam Span 28'-0". Determine the ultimate moment, Mu for the Center beam shown above assuming a simple span of 28'-0", given: 10-o", R : 10'4", h :5.6", b-14", h :3.6", (hs d + bottom cover), DL :350 psf and LL-100 psf. Assume the given dead load already indudes the weight of the concrete. c. d. Determine the nominal positive bending moment, Mn for the Center beam shown above, given: hi-5.5", bw-14", d-2,4", fy = 40 ksi, fc :3,000 psi, b-68 inches, As* 5.00 sq. inches. Also what is the steel strain? Determine the nominal positive bending moment, Ms for the Center beam shown above, given: h 4.5", bw 12", d 2'-8", fy Also what is the steel strain? e. 60 ksi, f'c 2,500 psi, by- 40", As-8-#9 bars

Explanation / Answer

a) Spandrel is an L shaped beam

Span /12=L/12 = 30/12=2.5' = 30 "

6*slab thickness=6*5=30"

half of clear distance to adjacent web=9/2=4.5'=54"

Therefore, effcetive flange width=30"

b)Span/4=28/4=7'=84"

8*slab thickness = 8*6=48"

Flange width = 48+48+12=108"

clear distance to next web=9'=108"

Flange width = 108+12=120"

Therefore, effective flange width = 84"

c)Tributary width of beam=10'

Dead load = 350 psf

Live load = 100 psf

Uniform dead load on beam = 350*10=3.5kip/ft

Uniform love load on beam=100*10=1 kip/ft

Factored load on beam = (1.2*3.5)+(1.6*1)=5.8 kip/ft

Ultimate moment in beam = 5.8*282/8=568.4 kip-ft

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