Perform a concrete mix design calculation using the parameters assigned to your

Question

Perform a concrete mix design calculation using the parameters assigned to your group in the handout provided. In the end, you must have the quantities for all the ingredients to be used in the mix. I am in group 3, thanks. Concrete Mix Design Procedure Determine Material Properties Caarse Aggregate -Specifix Geavity, G (Dimensionless) - Bulk Unit Weight, y (usually given in lbyf) -Nominal Maximum Aggregate Stze (inches o Fine Aggregabe . Specific Gravity, Gi-Dimensionless will be provided by the Instructor Fineness Modulus (Dimensionless o Water o Cement o ly Ash (If applicable) -Unit Weight, (624 b/f or 1,685 lb/yd -Specific Gravity, GMms(Dimensionless) (GMenes,-315) Specific Gravity, GoAy Ash (Dimensionless) (aply Ash = 28) Computation of Volume& Weight for each Constituent Material Water Determine the mix water content by weight using Table 7.8 in the textbook for the provided on page 3 of this document o Calculate the weight of water needed to produce 1 ft of concrete. o Caleulate the corresponding volume of water (unit weight, a 62.4 b/t or Cementitious Materials o Indludes Portland cement and other mineral admixtares such as Fly Ash, where applicable. Deterine the w/e ratio using Table 72 in testbook for mix design criteria provided on page 3 of this document. Round out your W/C to the nearest multiple oé 0.1 o Use w/c ratio (Ratio of weight of waber to weight of cementitious maberials) and weight of water to calculate weight of cementitious materials o If Fly Ash is a part of the mix design, calculate its weight and solid volume o Caleulate the Portland cement weight by subtracting the ly ash weight Caleulate the corresponding solid volume of Portland cement (use a cement specific gravity of 3.15) “ h and einer ,: wiwde/Gaw.xyi.) o o Determine the Coase Aggregate Factor (CAP) using Table 75 in the text for the aggregate data provided on page 3 of this document CAF corresponds to Bulk Volume of Coarse Aggregate per Unit Volume of Concrete produced with it, expeessed as a decimal. o o Calculate the bulk volume of the Coarse Aggregate o Caleulate the weight and solid volume of the Coarse Aggregate

Explanation / Answer

the design mix preparation has a number of steps to be followed ,

GRADE DESIGNATION GIVEN : M25

step 1 : We have to calculate the target mean strength ,

according to the details given for group 3

TARGET MEAN STRENGTH = fck + 1.65 s

= 25 + 1.65 (4)

=31.6 MPa (Approx)

step 2 : we have to select WATER CEMENT RATIO : Let us assume water cement ratio to 0.50  

step 3 : Calculation of water content

for the given size of aggregates (19mm) according to IS CODE water content is 186kg/m3 ( If plastcizer is used we can reduce by 20 % ) = 186 x 0.8 = 148.8 kg/m3

step 4 : We have to calculate cement content

Water cement ratio is 0.5

water content = 148.8 kg/m3

CEMENT CONTENT = 148.8 / 0.5 = 297.6 kg/m3 = 298 kg/m3 approx = 18.6 lb/ft3

step 5 : calculation of fine and coarse aggregate

volume of cement = 298/3.15x 1000 = 0.094m3 = 3.31 ft 3

volume of water = 148.8 / 1000 = 0.149 m3 = 5.26 ft 3

total weight = 0.094 + 0.149 = 0.243 m3 =8.58 ft 3

volume of fine and coarse aggregate = 1- 0.243 = 0.757 m3

VOLUME OF FINE AGGREGATE (F.A) = 0.757 X .33 = 0.25 m3 = 8.82 ft 3

VOLUME OF COARSE AGGEGRATE (C.A) = 0.757- 0.25 = 0.5 m3 = 17.65 ft 3

WEIGHT OF F.A = 0.25 X G X 1000 = 0.25 X 2.64X1000= 660 Kg/m3 = 41.20 lb/ft3

weight of C.A = 0.5X G COARSE X 1000 = 1290 Kg/m3  =80.53 lb/ft3

CALCULATION OF QUANTITIES material volume (ft3) calculated weight (lb) weight corrected for moisture( lb) WATER 5.26 9.28 CEMENT 3.31 18.6 FLYASH - - CA 17.65 80.53 AIR FA 8.82 41.20 CONCRETE MIX 1.0

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