is it possible that the book has a mistake in the shear diagram? cuz it takes x
ID: 1714473 • Letter: I
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is it possible that the book has a mistake in the shear diagram? cuz it takes x to be 0=<x<9 I calculate the shear at exactly 9 and it is zero, I have a confusion why did it take only x before 9 then it included the reaction at B
350 CHAPTER 7 INTERNAL FORCES for the beam show EXAMPLE 7.7 Draw the shear and moment diagrams for the Fig. 7-12a. are shown on the bean HITTIT -9 m (a) SOLUTION Support Reactions. The support reactions are show free-body diagram, Fig. 7-12c. Shear and Moment Functions. A free-body dia segment of the beam having a length x is shown in Fio proportional triangles, the distributed loading acting a segment has an intensity of w/x = 6/9 or w = (2/3).x. It a resultant force after the segment is isolated as a free-bo The magnitude of the resultant force is equal to (x) (?) force acts through the centroid of the distributed lo: equilibrium yields ody diagram for a leis wn in Fig. 7-12b. Due o acting at the end of th= (2/3).x. It is replaced s a free-body diagrar nal to (x)(x) = . 17 kN Zx kN/m the right end. Applying the two equations 9 - - - V = 0 9 kN +12F, = 0; (b) v = (0-1) EN MO) - 9x = 0 M = (0-) EN -m 16 kN/m (+XM = 0; 9 kN V (kN) V (KN) - 9 - 18 kN Shear and Moment Diagrams. The shear and moment di. shown in Fig. 7-12c are obtained by plotting Eqs. 1 and 2. The point of zero shear can be found using Eq. 1: 18 kN - x (m) –5.20 m V = 9 - M (kN·m) M = 9x - * = 5.20 m Mmax = 31.2 NOTE: It will be shown in Sec. 7.3 that this value of x ha represent the point on the beam where the maximum mome Using Eq. 2, we have 5.20 9x (m) (e) Mmax = (905.20) - (5.20). KN·m Fig. 7-12 = 31.2 kN·mExplanation / Answer
Text book solution is correct only. We can not define a function exactly at support or exactly at point load is acting. We will define it as just right it and just left to it. Exactly at the right support function becomes invalid. Shear force at support means shear force just left to it or just right to it but not exactly at the support.
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