This section has only one (1) problem. Use the space provided and attach additio

Question

This section has only one (1) problem. Use the space provided and attach additional sheets necessary. Show your work clearly and neatly for full credit. 1) For a 200 ft equal-tangent parabolic curve with the parameters listed below calculate/tabulate the full station elevations along that curve and calculate the stationa elevation of the lowest point on the curve. A-1.5090 grades meets a +2.50% grade at station 46 + 00 ft and elevation 895.00 ft. Lg, high/low 581 g1 82) with L in stations, gi in % Given Station for VPI: Station for BVC(VPC) Station VPI-L/2 Station for EVC(VPT)-Station VPI + L/2 Station BVC + L (sta) X (Sta) giX (r/2)x2 Elev (ft) Station 0.00 0.0 0.00 BVC

Explanation / Answer

Equal Tangent Parabolic Curve
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
VPI Station = 46+00.00

VPI Elevation = 895.00
g1 = -1.50%
g2 = +2.50%
Length = 200.00
BVC Station = 45+00.00
BVC Elevation = 896.50

Station x (Sta) g1*x r/2*x*x Elevation
==================================================================
47+00.00 2.00 -3.00 4.00 897.50
46+50.00 1.50 -2.25 2.25 896.50
46+00.00 1.00 -1.50 1.00 896.00
45+50.00 0.50 -0.75 0.25 896.00
45+00.00 0.00 -0.00 0.00 896.50
==================================================================

Minimum elevation = 895.94 @ station 45+75.00

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