The total resistance in the circuit in Figure 5-4 is: Select one: 90 Ohms + 10 O

Question

The total resistance in the circuit in Figure 5-4 is: Select one: 90 Ohms + 10 Ohms 90 Ohms 90 Ohms/10 Ohms 10 Ohms Kirchhoff's law for parallel circuits states that the: Select one: sum of the total currents flowing out of a junction equals the sum of the total currents flowing into that junction, sum of currents into a junction is equal to the difference of all the branch currents, sum of all branch voltages equal zero, total circuit resistance is less than the smallest branch resistor. In a parallel resistive circuit: Select one: the voltage applied divides between the branches. There is more than one current path between two points. The total circuit conductance is less than the smallest branch conductance, the total branch power exceeds the source power. What is the supply voltage when a 5 K ohm and a 4 K ohm resistor are in series and 6 V is measured across the smaller resistor? Select one: 1.35V 2V 6V 13.5 V

Explanation / Answer

1) total resistance=90+10=100 ohms.

2) a sum of the total currents flow out of a junction is equal to the sum of the currents flow in to that junction.

3) there is more than one current path between two points.

4) current flowing through 4kohm resistor is 6/4k=1.5 mapms

total voltage= (5+4)*10^3*1.5*10^-3=13.5 volts

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