If force, length and the time are selected as the three fundamental dimensions,
ID: 1717448 • Letter: I
Question
If force, length and the time are selected as the three fundamental dimensions, the units of mass in the SI system could be written as Develop the dimension of kinetic viscosity (v) using the F-L-T system A 3600N force acts on a 250cm^2 area at an angle of 60degree to the normal. The pressure (normal stress) acting on the area is (show your result in Pa): A liquid with a specific gravity of 1.2 fills a volume. If the mass in the volume 10 slug, What is the magnitude of the volume in ft^1? The mass of a car is 3.2 tom. which are evenly distributed to 4 tires, for a measured tire pressure of 32 psi Suppose the local air pressure is 100 kpa, compute the absolute pressure inside foe tire. Compute the contacting area between each tire and the ground using SI system.Explanation / Answer
density of water = mass /volume
1000 = mass / v
mass = v x 1000
1 x 1000
= 1000 kg
or F = mg
mass m = F /g
m = w /g
2) kinematic viscisity = VISCOSITY /DENSITY = FORCE X TIME / LENGTH ^2 X MASS /LENGTH ^3 = MASS X ACCELERATION X TIME / MASS /LENGTH
= MASS XLENGTH /TIME^2 X TIME /MASS / LENGTH
= LENGTH ^2 /TIME
= L^2 T^-1
force F = 3600 N AND 60 DEGREES TO NORMAL
AREA OF CROSS SECTION A = 250 CM^2 =250 / 10^-4
= 0.0250 M^2
NORMAL STRESS = FORCE / AREA
= 3600COS 60 /0.0250
72000 N/M^2 = 72000 Pa
4) mass / volume = density
mass is given m = 10 slugs
specific gravity(S)=1.2
density = S x 32.174
1.2 x 32.174
volume=weight /specific weight
specifc weight w = density x g
1.2 x 32.174 x32.174
volume v = mg / 1.2 x 32.174 x 32.174
= 10 / 1.2 x 32.174
Absolute pressure = atomospheric pressure + gauge preesure= 100 x 0.145 +128
1856 psi
= 0.259 ft^3
total pressure in all the tyres = 4 x 32
= 128 psi
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