A rescue helicopter lifts a 75-kg personstraight up by means of a cable. The per

Question

A rescue helicopter lifts a 75-kg personstraight up by means of a cable. The person has an upwardacceleration of 0.70 m/s2 and is lifted from restthrough a distance of 12 m. (a) What is the tension in the cable?
1(No Response) N

(b) How much work is done by the tension in the cable?
2(No Response) J

(c) How much work is done by the person's weight?
3(No Response) J

(d) Use the work-energy theorem and find the final speed of theperson.
4(No Response) m/s
(a) What is the tension in the cable?
1(No Response) N

(b) How much work is done by the tension in the cable?
2(No Response) J

(c) How much work is done by the person's weight?
3(No Response) J

(d) Use the work-energy theorem and find the final speed of theperson.
4(No Response) m/s

Explanation / Answer

    mass, M = 75 kg     acceleration, a = 0.7 m/s^2     displacement, S = 12 m     Initial velocity, U = 0     Final velocity = V (a)     Tension, T = M ( g + a )                     = 75 ( 9.8 + 0.7 ) = 787.5 N (b)     Work, W = T * S = 787.5 * 12 = 9450 J (c)     Work, W = ( M g ) * S = 75 * 9.8 *12 = 8820 J (d)     Net force , F = M a     Work done = Change in kinetic energy     F S = ( 1/2 ) M ( V2 - U2)     M a S = ( 1/2 ) M ( V2 -U2 )          a S = ( 1/2 ) (V2 - U2 )          0.7 * 12 = 0.5 * V2             V = 4.1 m/s

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