In the neck of the picture tube of a certain black-and-whitetelevision set, an e
ID: 1722248 • Letter: I
Question
In the neck of the picture tube of a certain black-and-whitetelevision set, an electron gun contains two charged metalic plates2.60 cm apart. An electric forceaccelerates each electron in the beam from rest to 9.40% of the speed of light over this distance.(Ignore the effects of relativity in your calculations.)(a) Determine the kinetic energy of theelectron as it leaves the electron gun. Electrons carry this energyto a phosphorescent material on the inner surface of the televisionscreen, making it glow.
1 J
(b) For an electron passing between the plates in the electron gun,determine the magnitude of the constant electric force acting onthe electron.
2 N
(c) Determine the electron's acceleration as it passes between theplates.
3 m/s2
(d) Determine the time of flight as the electron passes between theplates.
4 s (a) Determine the kinetic energy of theelectron as it leaves the electron gun. Electrons carry this energyto a phosphorescent material on the inner surface of the televisionscreen, making it glow.
1 J
(b) For an electron passing between the plates in the electron gun,determine the magnitude of the constant electric force acting onthe electron.
2 N
(c) Determine the electron's acceleration as it passes between theplates.
3 m/s2
(d) Determine the time of flight as the electron passes between theplates.
4 s
Explanation / Answer
KE = 1/2 m v2 = 1/2 * 9.11*10E-31 * (.094 *3*10E8)2 = 3.62 * 10E-16 J W = F d = KE F. = 3.62 * 10E-16 / .026 = 1.39 * 10E-14 N a = F / m = 1.39 *10E-14 / 9.11 * 10E-31 = 1.53 * 10E16m/s2 s = 1/2 a t2 t = (2 s / 1.53 * 10E16) = 1.84 * 10E-9 sec t = (2 s / 1.53 * 10E16) = 1.84 * 10E-9 secRelated Questions
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