a 350 g stone is swung in a circular path, on a 60 cm lengthof string and in a v
ID: 1722535 • Letter: A
Question
a 350 g stone is swung in a circular path, on a 60 cm lengthof string and in a vertical plane. The tangential velocity at thebottom of the circle is 7.2 m/s. Hint this is partially an energyproblem. a. what is the tension in the string at the bottom of thecircle? b. what is the tangential speed of the stone at the top of thecircle? c. what is the tension in the string at the top of thecircle? d. what is the minimum speed for the stone at the top of thecircle such that the string will not collapse? PLEASE SHOW ALL WORK a 350 g stone is swung in a circular path, on a 60 cm lengthof string and in a vertical plane. The tangential velocity at thebottom of the circle is 7.2 m/s. Hint this is partially an energyproblem. a. what is the tension in the string at the bottom of thecircle? b. what is the tangential speed of the stone at the top of thecircle? c. what is the tension in the string at the top of thecircle? d. what is the minimum speed for the stone at the top of thecircle such that the string will not collapse? PLEASE SHOW ALL WORKExplanation / Answer
Given that the mass of stone is m = 0.350 kg Length of string is L = 0.60 m Tangential velocity at bottom is Vb = 7.2m/s -------------------------------------------------------- (a) Tension in the string at bottom is T = mg + mVb2 / L = ----------- N (b) Apply conservation of energy at top andbottom (1/2)mVb2 = mg(2L) +(1/2)mVt2 Vb2 = 4gL + Vt2 then we get Vt = ---------m/s (c) Tension in the string at top is T = mg -mVt2 / L = ----------N (d) To complete circle T = 0 at the top then mg = mVt2 / L then we get Vt = --------- m/s
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