A 2.2-kg cart is rolling along a frictionless, horizontal tracktowards a 1.2-kg

Question

A 2.2-kg cart is rolling along a frictionless, horizontal tracktowards a 1.2-kg cart that is held initially at rest. The carts areloaded with strong magnets that cause them to attract one another.Thus, the speed of each cart increases. At a certain instant beforethe carts collide, the first cart's velocity is +3.3 m/s, and thesecond cart's velocity is -1.2 m/s. (a) What isthe total momentum of the system of the two carts at this instant?(b) What was the velocity of the first cart whenthe second cart was still at rest?


(a) NumberUnits Nounits°skgmm/sm/s^2Nkg?m/s or N?sJW
(b) Number UnitsNounits°skgmm/sm/s^2Nkg?m/s or N?sJW

Explanation / Answer

Total momentum =2.2*3.3+1.2*(-1.2) =5.82 Since momentum always conserve total mometum =constant 5.82 =2.2*x+0 x=2.645m/s

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.