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After pushing a 6kg bowling ball for 0.25s, it rolls down thealley at a speed of

ID: 1724171 • Letter: A

Question

After pushing a 6kg bowling ball for 0.25s, it rolls down thealley at a speed of 5m/s. How much force did you have to apply togive it the translational motion, if it started from rest? A)120 N B)58.8N C)36 N D)20N E)7.5N Hint: F=ma We need to find a. Given: t = 0.25s, v=5 m/s a=x/v=20m/s2 m=6kg, F=6*20kgm/s2 After pushing a 6kg bowling ball for 0.25s, it rolls down thealley at a speed of 5m/s. How much force did you have to apply togive it the translational motion, if it started from rest? A)120 N B)58.8N C)36 N D)20N E)7.5N Hint: F=ma We need to find a. Given: t = 0.25s, v=5 m/s a=x/v=20m/s2 m=6kg, F=6*20kgm/s2

Explanation / Answer

we know tha      F = ma here a is given by    a = v/t = 5m/s / 0.25s = 20m/s2 Now F = (6kg) (20m/s2 ) = 120N Now F = (6kg) (20m/s2 ) = 120N
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