A child in a boat throw a 6.40 kg package out horizontallywith a speed of 10.0 m

Question

A child in a boat throw a 6.40 kg package out horizontallywith a speed of 10.0 m/s. (a) Calculate the velocity of the boatimmediately after, assuming it was initally at rest. The mass ofthe child is 26.0 kg, and that of the boat is 45.0 kg. (b)calculate the KE gained. Explain where it's origin. Ignore waterresistance is wrong. I got part (b) wrong on my homework, I don't know how to doit. Can someone please explain to me. A child in a boat throw a 6.40 kg package out horizontallywith a speed of 10.0 m/s. (a) Calculate the velocity of the boatimmediately after, assuming it was initally at rest. The mass ofthe child is 26.0 kg, and that of the boat is 45.0 kg. (b)calculate the KE gained. Explain where it's origin. Ignore waterresistance is wrong. I got part (b) wrong on my homework, I don't know how to doit. Can someone please explain to me.

Explanation / Answer

From law of conservation of momentum m1 v1 = m2v2    v2 = m1 v1 / m2 = (6.4kg) (10m/s) / (26+45) = 0.9m/s The kinetic energy gained    K = 1/2 m2 v22 = 1/2 (26+45) (0.9)2 = 28.75 J

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