A 25kg chair initially at rest on a horizontal floor requiresa 165 Newton horizo

Question

A 25kg chair initially at rest on a horizontal floor requiresa 165 Newton horizontal forceto set it in motion. Once the chair isin motion, a 127 Newton horizontal force keeps it moving at aconstant velocity. How do I calculate the static friction between the chair andthe floor? A 25kg chair initially at rest on a horizontal floor requiresa 165 Newton horizontal forceto set it in motion. Once the chair isin motion, a 127 Newton horizontal force keeps it moving at aconstant velocity. How do I calculate the static friction between the chair andthe floor?

Explanation / Answer

     Given that the mass of chair is m = 25kg      Force required to set in motion is F1 =165 N      Force required to keep the body movingwith constant velocity is F2 = 127 N --------------------------------------------------------------------------------------------- (a) The static friction force is f = F1                                     *N = 165N                                     mg = 165 N                                      = 165 N / mg                                            = -------- this is the coefficient of static friction (b) IF the body moving with constant velocity                      Applied force = kinetic friction                                F2 = f                                127N = k*mg                              k = 127N /mg                                   = ----------- This is the coefficient of kinetic friction

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