2nd question!! A position-versus-time plot for an objectundergoing simple harmon

Question

2nd question!! A position-versus-time plot for an objectundergoing simple harmonic motion is given in the figure . Rank the six points indicated in the figure inorder of decreasing velocity. Rank the six points indicated in the figurein order of decreasing acceleration.
Rank points from highest to lowestacceleration. To rank items as equivalent, overlap them. Rank the six points indicated in the figurein order of decreasing acceleration.
Rank points from highest to lowestacceleration. To rank items as equivalent, overlap them.

Explanation / Answer

The max velocity vmax = a =0.5m (2*3.14/ 4s) = 0.785 m/s which is more than 0.5m/s   (b) the velocity is maximum at A = D >, B = E > C = F , the acceleration C =F > B=E > A = D    the acceleration is max at extream positions andminimum at mean position         

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