A standingwave on a tight string experiment is set up in thelaboratory. One end

Question

A standingwave on a tight string experiment is set up in thelaboratory. One end of the string is attached to anoscillator that vibrates with a frequency of 60 Hz. The otherend of the string passes over a pulley and is attached to amass. The distance between the oscillator and the pulley is1.2 m. When the oscillator is turned on, six loops areobserved on the string. The linear mass density of the stringis 1.4 g/m.

a.       A. What is the wavelength ofthe standing wave?

b.     B. What is the wave speed of the standing wave?

c.     C. How much mass is hanging on the string?

Explanation / Answer

(b) The speed of the wave is    v = f    = (60Hz) (0.4m) = 24m/s (c) Now    v = [ T / ] 1/2    v2 = [ T/ ]   then    T = v2   = (24)2 (1.4*10-3 kg/m)    = 0.806 N therefore    mg = 0.806N then mass m = 0.806 / 9.8 = 0.082 kg or 82 gm    v2 = [ T/ ]   then    T = v2   = (24)2 (1.4*10-3 kg/m)    = 0.806 N therefore    mg = 0.806N then mass m = 0.806 / 9.8 = 0.082 kg or 82 gm

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