A magnetic field is perpendicular to the plane of a single-turncircular coil. Th

Question

A magnetic field is perpendicular to the plane of a single-turncircular coil. The magnitude of the field is changing, so that anemf of 0.55 V and a current of3.7 A are induced in the coil. Thewire is the re-formed into a single-turn square coil, which is usedin the same magnetic field (again perpendicular to the plane of thecoil and with a magnitude changing at the same rate). What emf andcurrent are induced in the square coil? emf 1 V current 2 A

In each of two coils the rate of change of the magnetic flux in asingle loop is the same. The emf induced in coil 1, which has171 loops, is 3.28 V. The emf induced in coil 2 is 5.29 V. How many loops does coil 2 have?


In each of two coils the rate of change of the magnetic flux in asingle loop is the same. The emf induced in coil 1, which has171 loops, is 3.28 V. The emf induced in coil 2 is 5.29 V. How many loops does coil 2 have?
emf 1 V current 2 A

Explanation / Answer

changing rate of magnetic field = B' for the circular ring: emf = B'*r2 = 0.55V, current I = /R = 3.7 A, where R = (2r)/A (A isthe cross section area) for the square ring: emf ' = B'*a2 = ?, current I'= '/R' = ?, where R' = (4a)/A note 2r = 4a, so a = r/2, a2 =2r2/4 =(/4)*(r2) ' = B'*(r2) *(/4) = (/4) =0.43 V R' = R I' = (/4)I = 2.9 A N = 171/3.28 * 5.29 = 276

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