To demonstrate standing waves, one end of a string is attachedto a tuning fork w

Question

To demonstrate standing waves, one end of a string is attachedto a tuning fork with frequency 180Hz. The tuning fork is ona stand to the right. The other end of the string passes overa pulley and is connected to a suspended mass M which is on theleft. The value of M is such that the standing wave patternhas four loops. The length of the string from the tuning forkto the point where the string touches the top of the pulley is1.80m. The linear density of the string is 1.0 x10-4 kg/m and remains constant throughout theexperiment. Determine the wavelength of the standing wave Determine the speed of transverse waves along the string The speed of waves along the string increases with increasingtension in the string. Indicate whether value of M should beincreased or decreased to double number of loops in standing wavepattern. Why If a poin on the strin at an antimode moves a total verticaldistance of 5 cm during one complete cycle what is the amplitude ofthe standing wave? To demonstrate standing waves, one end of a string is attachedto a tuning fork with frequency 180Hz. The tuning fork is ona stand to the right. The other end of the string passes overa pulley and is connected to a suspended mass M which is on theleft. The value of M is such that the standing wave patternhas four loops. The length of the string from the tuning forkto the point where the string touches the top of the pulley is1.80m. The linear density of the string is 1.0 x10-4 kg/m and remains constant throughout theexperiment. Determine the wavelength of the standing wave Determine the speed of transverse waves along the string The speed of waves along the string increases with increasingtension in the string. Indicate whether value of M should beincreased or decreased to double number of loops in standing wavepattern. Why If a poin on the strin at an antimode moves a total verticaldistance of 5 cm during one complete cycle what is the amplitude ofthe standing wave?

Explanation / Answer

The wavelength is given as        4 loops ( / 2) =1.8m           = 1.8m / 2              = 0.9m Speed of thewave in the string is         V = f            = ( 180)(0.9)            = 162m/s The tension is propotionaal to the Mass attached. The amplitude is 5cm.           

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