a mechanic jacks a car up to an angle of 6.0 o to change the front tires. the ca

Question

a mechanic jacks a car up to an angle of 6.0o to change the front tires. the car is 2.9m long and has a mass of1130 kg. its center of mass is located 1.12 m from the frontend. the rear wheels are .40m from the back end. Calculate the torque exerted by the car around the backwheels. (Nm, is it clockwise or counterclockwise?) a mechanic jacks a car up to an angle of 6.0o to change the front tires. the car is 2.9m long and has a mass of1130 kg. its center of mass is located 1.12 m from the frontend. the rear wheels are .40m from the back end. Calculate the torque exerted by the car around the backwheels. (Nm, is it clockwise or counterclockwise?)

Explanation / Answer

    Angle of inclination, = 6o     Length of the car, L = 2.9 m     Mass of the car, M = 1130 kg     Weight of the car, F = M g                                   = 1130 * 9.8                                   = 11074 N     Distance of center of mass from front end, X =1.12 m     Distance of rear wheels from back end, Y = 0.4m     Distance of center of mass from rear wheels, d =L - ( X + Y )                                                                           = 2.9 - ( 1.12 + 0.4 )                                                                           = 1.38 m     Torque exerted by the car around the backwheels, = F d Cos                = 11074 *1.38 * cos 6o                = 15198.4N.m   ( Clockwise )

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