A billiard ball moving at 5.10m/s strikes a stationary ball of the same mass. Af
ID: 1727660 • Letter: A
Question
A billiard ball moving at 5.10m/s strikes a stationary ball of the same mass. After thecollision, the first ball moves at 4.18m/s, at an angle of 35.0° with respectto the original line of motion. (a) Find the velocity (magnitude and direction)of the second ball after collision.1 m/s
2° (with respect to the original line ofmotion, include the sign of your answer; consider the sign of thefirst ball's angle)
(b) Was the collision inelastic or elastic? 3 inelastic elastic A billiard ball moving at 5.10m/s strikes a stationary ball of the same mass. After thecollision, the first ball moves at 4.18m/s, at an angle of 35.0° with respectto the original line of motion. (a) Find the velocity (magnitude and direction)of the second ball after collision.
1 m/s
2° (with respect to the original line ofmotion, include the sign of your answer; consider the sign of thefirst ball's angle)
(b) Was the collision inelastic or elastic? 3 inelastic elastic (a) Find the velocity (magnitude and direction)of the second ball after collision.
1 m/s
2° (with respect to the original line ofmotion, include the sign of your answer; consider the sign of thefirst ball's angle)
(b) Was the collision inelastic or elastic? 3 inelastic elastic 3 inelastic elastic 3 inelastic elastic 3
Explanation / Answer
for the simplicity let us choose the x-axis to bealong the line of motion
(a)
if we apply the conservation of momentum in the xdirection we get
m (5.10 m / s) + 0 = m (4.18 m / s)cos35.0o + m v2f cos
v2f cos = ........ m / s......... (1)
if we apply the conservation of momentum inthe y direction we get
0 = m (4.18 m / s)sin35.0o + m v2f sin
v2f sin = - ........ m /s .......... (2)
divide (2) / (1)
tan = ..........
= - .........o
v2f = ......... m / s at -60.0o
(b)
the initia; kinetic energy is given by
KEi = (1 / 2) mv1i2 + 0
= (1 / 2) m(4.18 m / s)2
KEf = (1 / 2) m v1f2+ (1 / 2) m v2f2
if KEf = KEi then the collisionis an elastic collision
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